3b^2-4=284

Solution for 3b^2-4=284 equation:

3b^2-4=284

We move all terms to the left:

3b^2-4-(284)=0

We add all the numbers together, and all the variables

3b^2-288=0

a = 3; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·3·(-288)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{6}}{2*3}=\frac{0-24\sqrt{6}}{6}
=-\frac{24\sqrt{6}}{6}
=-4\sqrt{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{6}}{2*3}=\frac{0+24\sqrt{6}}{6}
=\frac{24\sqrt{6}}{6}
=4\sqrt{6}
$